math
posted by Sidney .
Solve for x:
[Sixth root of 27]+[cube root of x] = 6/(3[square root of 3]

27^(1/6) + x^(1/3) = 6/(3  √3)
(3^3)^(1/6) + x^(1/3) = 6/(3  √3)[(3+√3)/(3+√3)]
3^(1/2) + x^(1/3) = 3 + 2√3
x^(1/3) = 3 + √3)
x = (3+√3)^3
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