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7. At pH 7.4 a weak organic acid with a pKa of 6.4 would be 60% ionized

% Ionization =[(H^+)/(acid)]*100 = 3.98 x 10^-8
HA ==> H^+ + A^
K = (H^+)(A^-)/(HA)
K = (H^+)(A^-)/[HA-(H^+)] Plug in 3.98E-7


    I don't get 60%. Is that your answer? An answer from your notes?

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