Calculus - dimensions of a box?

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A rectangular box with a square bottom and a volume of 256 cubic feet is to be constructed. The top and bottom cost $ .10 per square foot to make and the four sides cost $ .05 per square foot to make. Find the approximate dimensions of the box which would minimize its cost.

  • Calculus - dimensions of a box? -

    let each side of the base be x ft
    let the height of the box be y ft
    V= (x^2)(y) = 256
    y = 256/x^2

    form the cost equation ....
    C = 2(.10)x^2 + 4(.05)xy
    = .2x^2 + 2x(256/x^2)
    = .2x^2 + 512/x

    C' = .4x - 512/x^2 = 0 for min of C

    I get x^3 = 1280
    x = 10.86 and y = 2.17

    check my arithmetic

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