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One morning, 8/9 of the customers at the diner ordered coffee. Regular coffee was ordered three times as much as flavored coffee. What fractional part of the customers orderd flavored coffee?
I did it this way 8/9x3/1= 24/9=8/3
It is wrong so please show me how to do this problem

First I would choose a number divisible by 9 to use as an example.
I chose 81.
If 8/9 of the customers ordered coffee, that's 8/9*81 = 72 customers.
If reg coffee was ordered three times as much as flavored, then you want to set it up like this:
3x + x = 72
4x = 72
x = 18
So 18 people ordered flavored coffee. 3(18)=54, so 54 people ordered regular coffee. If the total was 81 customers, then 18/81 ordered flavored coffee which reduces to 2/9.

First I would choose a number divisible by 9 to use as an example.
I chose 81.
If 8/9 of the customers ordered coffee, that's 8/9*81 = 72 customers.
If reg coffee was ordered three times as much as flavored, then you want to set it up like this:
3x + x = 72
4x = 72
x = 18
So 18 people ordered flavored coffee. 3(18)=54, so 54 people ordered regular coffee. If the total was 81 customers, then 18/81 ordered flavored coffee which reduces to 2/9.

2/9

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