showing by calculations how would i prepare the following solutions :
200ml stock solution of 1M NaOH (mwt 40g/mol)
M = moles/L soln
Solve for moles (you have M and L).
moles = grams/molar mass
Solve for grams.
To prepare a 200 ml stock solution of 1M NaOH with a molecular weight of 40 g/mol, you can follow these steps:
Step 1: Calculate the amount of NaOH needed:
Molarity (M) = moles of solute / liters of solution
Given:
Molarity (M) = 1 M
Volume (V) = 200 ml = 0.2 L
Using the above formula, rearrange to solve for moles of solute:
moles of solute = Molarity (M) x liters of solution (V)
moles of solute = 1 M x 0.2 L
moles of solute = 0.2 moles
Step 2: Calculate the mass of NaOH needed:
mass = moles x molecular weight
mass = 0.2 moles x 40 g/mol
mass = 8 grams
Therefore, to prepare a 200 ml stock solution of 1M NaOH, you will need 8 grams of NaOH.
To prepare a 200 ml stock solution of 1M NaOH, you will need to calculate the amount of NaOH needed by using the formula:
Number of moles = Volume (in liters) × Molarity
Step 1: Convert the volume of the stock solution to liters.
200 ml = 200/1000 = 0.2 L
Step 2: Calculate the number of moles of NaOH needed.
Number of moles = 0.2 L × 1 M = 0.2 moles
Step 3: Calculate the mass of NaOH needed using the molar mass (molecular weight).
Mass = Number of moles × Molar mass
Mass = 0.2 moles × 40 g/mol = 8 grams
Therefore, to prepare a 200 ml stock solution of 1M NaOH, you need to dissolve 8 grams of NaOH in 200 ml of water. Make sure to wear protective gloves and goggles when handling NaOH as it is a strong base and can cause chemical burns.