given a mean of 8 and a standard deviation of 0.7 what is the z-score of the value 9 rounded to the nearest tenth
To find the z-score, we can use the formula:
z = (x - μ) / σ
Where:
- z is the z-score
- x is the value we want to find the z-score for (in this case, 9)
- μ is the mean (in this case, 8)
- σ is the standard deviation (in this case, 0.7)
Let's substitute the values into the formula:
z = (9 - 8) / 0.7
z = 1 / 0.7
z ≈ 1.43
Rounded to the nearest tenth, the z-score of the value 9 is approximately 1.4.