# Calc

posted by Erica

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis.

y = cube rt. (x) + 2

Thank you so much!!

1. helper

You need parentheses.

y = (cubert(x)) + 2
y = (cubert(x + 2))

2. helper

I hit post, just as I realized what you meant. Sorry.

Since the parentheses are around the (x),
you most likely mean,
y = (cubert(x)) + 2.

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