Find an equation of the line having the given slope and containing the given point
m=7/8,(2,-5)
(y+5) = (7/8)(x-2)
8y + 40 = 7x - 14
7x - 8y = - 54
To find the equation of a line given the slope and a point, you can use the point-slope form of a linear equation. The point-slope form is given by:
y - y1 = m(x - x1)
where m represents the slope, and (x1, y1) is a point on the line.
In this case, the given slope is 7/8, and the point on the line is (2, -5). Plugging these values into the point-slope form, we get:
y - (-5) = 7/8(x - 2)
Simplifying the equation by multiplying out the terms, we have:
y + 5 = 7/8x - 7/4
Next, we need to isolate y on one side of the equation. To do this, we subtract 5 from both sides:
y = 7/8x - 7/4 - 5
Simplifying further, we combine the constant terms:
y = 7/8x - 7/4 - 20/4
y = 7/8x - 27/4
Therefore, the equation of the line with a slope of 7/8 and passing through the point (2, -5) is y = 7/8x - 27/4.