posted by Marissa .
while on the moon, the Apollo astronauts enjoyed the effect of a gravity much smaller than that on earth. if Neil Armstrong jumped up on the moon with an initial speed of 1.51 m/s to a height of 0.700m, what amount of gravitational acceleration did he experience?
Using conservation of energy,
(1/2)M Vo^2 = M g'H, so
g' = Vo^2/(2H)
is the value of the acceleration of gravity on the moon.
I get 1.63 m/s^2
1.63m/s^2 is not the correct answer, take for example this:
10=5g What is 'g'?
1.63 m/s^2 is the correct answer
Marko 1.51^2 /g doesn't equal 2.2801g it equals 2.2801/g. So your answer is the reciprical of the right answer. Nice try though.