Suppose that a natural number from 1 through 9 is selected at random. What is the probabiliy that the number selected is odd if you know that it is prime?
Please identify the school subject so we know clearly what it is. Mat means nothing to me, but Math does.
Sra
The only prime numbers in that range are 1, 3, 5 and 7. They are all odd, 100%.
Sorry, Assuming you count 1 as a prime number, and 9 is not. 4/5 = 80% If you don't count 1, it is 3/5 = 60%.
To determine the probability that the number selected is both prime and odd, we need to understand the number of primes and odd numbers in the given range.
First, let's list the prime numbers between 1 and 9: 2, 3, 5, and 7. These are the only prime numbers in the given range.
Next, let's list the odd numbers between 1 and 9: 1, 3, 5, 7, and 9.
Now, we need to find the favorable outcomes for the event "the number selected is both prime and odd." From our lists, we see that there are three numbers that satisfy this condition: 3, 5, and 7.
Therefore, the probability of selecting a number from 1 to 9 that is both prime and odd is 3 out of the total 4 prime numbers, which is 3/4 or 0.75.