# Algebra 2

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If f(x)=3^2 g(x)= 1/6+x find the following and give the domain

(f+g) (x) (3^2) + (1/6+x) x is all real numbers and x is not equal to 6
(f-g) (x) (3^2) - (1/6+x) 3^2 -6-x x is all real numbers and x is not equal to -6
(f x g) (x) I do not understand
(f/g) (x) 3^2/6-x x is all real numbers and x is not equal to 6

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