# Algebra 2

posted by
**Samantha**
.

If f(x)=3^2 g(x)= 1/6+x find the following and give the domain

(f+g) (x) (3^2) + (1/6+x) x is all real numbers and x is not equal to 6

(f-g) (x) (3^2) - (1/6+x) 3^2 -6-x x is all real numbers and x is not equal to -6

(f x g) (x) I do not understand

(f/g) (x) 3^2/6-x x is all real numbers and x is not equal to 6