Algebra 2
posted by Samantha .
If f(x)=3^2 g(x)= 1/6+x find the following and give the domain
(f+g) (x) (3^2) + (1/6+x) x is all real numbers and x is not equal to 6
(fg) (x) (3^2)  (1/6+x) 3^2 6x x is all real numbers and x is not equal to 6
(f x g) (x) I do not understand
(f/g) (x) 3^2/6x x is all real numbers and x is not equal to 6
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