# Calculus

posted by Amanda

Find the exact area below the curve (1-x)*x^9 and above the x axis

1. helper

Were you given (a,b) values?

From x = ? to ?

2. MathMate

First you define the function as
f(x)=(1-x)*x^9

Inspection of its 10 factors should indicate that the function crosses the x-axis at two points (0,0), (0,1).

The leading coefficient is -x^10, which means that the major part of the function is concave downwards, and is above the x-axis only between x=0 and 1.

Check: f(0.5)=(1-0.5)*0.5^9 > 0

The area sought is thus between the limits of x=0 and x=1.

The area below a curve f(x) is
∫f(x)dx between the limits of integration (0 to 1).

The function can be split up into a polynomial with two terms, and is thus easy to integrate.

Inspection of the graph between 0 and 1 and an approximate calculation of the area shows that the area should be in the order of 0.01. Post your answer for a check if you wish.

Here's a graph of the function between 0 and 1.

http://img411.imageshack.us/img411/1397/1296510221.png

3. helper

I just looked at the graph.

You want the area from x = 0 to x = 1.

| = integrate symbol
| x^9(1 - x)
| x^9 - x^10

Then plug in x, from 0 to 1.

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