Applied Business Math/Colleg student
posted by Nicole .
Solve the problem and reduce to lowest terms? 2/3+1/6+11/12=

Applied Business Math/Colleg student 
Ms. Sue
2/3+1/6+11/12=
First you need to change these fractions to equivalent fractions with a common denominator.
If you post the equivalent fractions, we'll be glad to help you solve this problem. 
Applied Business Math/Colleg student 
Bosnian
(2/3)=(2*4)(3*4)=(8/12)
(1/6)=(2*1)/(2*6)=(2/12)
2/3+1/6+11/12=
=(8/12)+(2/12)+(11/12)
=(21/12)
=(12+9)/12
=(12/12)+(9/12)
=1+(3*3)/(3*4)
= 1 3/4
=(4/4)+(3/4)
=7/4 
Applied Business Math/Colleg student 
Anonymous
6 ⅚ – 17/18
Respond to this Question
Similar Questions

algebra
x^3  x^2 __________ x^4 reduce to lowest terms? 
math
Add the fractions 2/3, 3/8, and 5/12 and reduce your answer to lowest terms. A. 10/24 C. 1 11/24 B. 25/24 D. 1 1/2 would you add 2/24, 3/24, and 5/24 which equals 10/24 but I don't understand the lowest terms. 
MATH
can some one please help to solve this problem. Add. reduce to lowest terms, if possible 3/y+3+y+7y9+/7/y3 
Math
I am having trouble understanding how to reduce fractions to its lowest term... All I can understand is I have to find the lowest number that will divide into both numerator and denominator. How do I understand the solution on how … 
Math
Solve; multiply; then reduce to lowest terms 5 1/2 * 3/4 
Math
solve; divide; then reduce to lowest terms 1 4/7 / 4/10 and divide; then reduce to lowest terms 14/3 / 2 5/7 
Math
Solve: Subtract; then reduce answer to lowest terms 5/22  1/41 
math
round 0.8394263 to the nearest hundredthousndth. Add the fractions 2/3,3/8 and 5/12 reduce to lowest terms subtract the fraction 7 4/ from 18 6/15 reduce answer in lowet terms 
Math
Solve the following problem and reduce to lowest terms (mixed number or improper fraction). 2/3 + 1/6 +11/12 
Math
Solve the following problem and reduce to lowest terms (mixed number or improper fraction). 2/3 + 1/6 +11/12