a number n is divided by 3 and the result is multiplied by 7 . then subtrat from the result to give 36 . what is the original number?
To find the original number, we need to follow the steps given in the problem.
Let's break it down:
Step 1: Divide the original number, n, by 3.
Result of Step 1: n/3
Step 2: Multiply the result of Step 1 by 7.
Result of Step 2: 7*(n/3) = (7/3)*n
Step 3: Subtract 36 from the result of Step 2.
Result of Step 3: (7/3)*n - 36
According to the problem, the result of Step 3 should be equal to the original number, n.
Setting up the equation:
(7/3)*n - 36 = n
To solve for n, we can simplify the equation:
7n/3 - 36 = n
Multiply both sides of the equation by 3 to eliminate the denominator:
7n - 108 = 3n
Subtract 3n from both sides:
7n - 3n = 108
Simplify:
4n = 108
Divide by 4:
n = 27
So, the original number is 27.
Is this the exact wording of the problem?
Assuming "then subtract from result" is referring to the unknown number n,
7(n/3) - n = 36
7n - 3n = 108
4n = 108
n = 27