HOW MANY MOLES OF HCL ARE REQUIRED TO PRODUCE 4.50 MOLES OF ZnCL2?
To determine the number of moles of HCl required to produce 4.50 moles of ZnCl2, we need to use the balanced chemical equation for the reaction between HCl and ZnCl2.
The balanced equation is:
2HCl + Zn -> ZnCl2 + H2
From the equation, we can see that 2 moles of HCl are required to produce 1 mole of ZnCl2.
So, we can set up a proportion:
2 moles HCl / 1 mole ZnCl2 = x moles HCl / 4.50 moles ZnCl2
Cross-multiplying, we get:
2 moles HCl * 4.50 moles ZnCl2 = x moles HCl * 1 mole ZnCl2
9 moles HCl = x moles HCl
Therefore, to produce 4.50 moles of ZnCl2, 9 moles of HCl are required.