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Rectangle ABCD is 12 inches long and has a perimeter of 54 inches. Rectangle LMNO is similar to rectangle ABCD and is 2.4 feet long. What is the width of the rectangle LMNO?

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    Perimeter ABCD = 54
    L = 12 in

    Perimeter LMNO = x
    L = 2.4 ft = 28.8 in

    P = 2w + 2L

    Use Ratio to find x (perimeter LMNO)
    12/28.8 = 54/x
    Cross multiply
    12x = 1555.2
    x = 129.6

    LMNO P = 129.6
    L = 28.8
    P = 2w + 2L
    129.6 = 2w + 2(28.8)

    Solve for w, width of LMNO

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