A brick is released with no initial speed from the roof of a building and strikes the ground in 1.50 {s}, encountering no appreciable air drag.

A. How tall, in meters, is the building?

B.How fast is the brick moving just before it reaches the ground?

a. h = 0.5gt^2

h = 0.5 * 9.8 * (1.5)^2 = 11m.

b. V = gt = 9.8 * 1.5 = 14.7m/s.

A. To find the height of the building, we can use the equation of motion for vertically falling objects: h = (1/2)gt^2. In this case, the time taken is 1.50 s, and the acceleration due to gravity is approximately 9.8 m/s^2. Substituting these values into the equation, we get:

h = (1/2)(9.8 m/s^2)(1.50 s)^2 = 11.025 m.

Therefore, the height of the building is approximately 11.025 meters.

B. To find the speed of the brick just before it reaches the ground, we can use the formula: v = gt, where v is the final velocity, g is the acceleration due to gravity, and t is the time taken.

Substituting the values into the equation, we get:

v = (9.8 m/s^2)(1.50 s) = 14.7 m/s.

Therefore, the brick is moving at approximately 14.7 m/s just before it reaches the ground.

To solve this problem, we can use the equations of motion under constant acceleration. In this case, the only force acting on the brick is gravity, which causes it to accelerate downwards.

A. To find the height of the building, we need to determine the distance the brick falls in 1.50 seconds.

The relevant equation of motion is:
h = (1/2)gt^2

Where:
h is the height of the building,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time (1.50 s).

Plugging in the values, we have:
h = (1/2)(9.8 m/s^2)(1.5 s)^2
h = 11.025 m

Therefore, the height of the building is approximately 11.025 meters.

B. To determine the speed of the brick just before it reaches the ground, we need to calculate the final velocity using the equation of motion:

v = gt

Where:
v is the final velocity,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time (1.50 s).

Plugging in the values, we have:
v = (9.8 m/s^2)(1.5 s)
v = 14.7 m/s

Therefore, the speed of the brick just before it reaches the ground is approximately 14.7 meters per second.

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