posted by lisa .
A dehydrated patient needs a 7.9% saline IV. Unfortunately, the hospital only has bags of 3% and 10% saline solutions. How many liters of each of these solutions should be mixed together to yield 3 liters of the desired concentration?
I answered your post below with this same question. Please check to see if your post was answered before re-posting.
I pasted the answer here for you.
x = liters of 3% solution
3 - x = liters of 10% solution
.03x = value 3% solution
.10(3 - x) = value 10% solution
3 = liters of 7.9% mixture
.079(3) = 0.237 = value 7.9% mixture
.03x + .10(3 - x) = 0.237
Solve for x, which is number of liters of 3% solution.
(3 - x) = number of liters of 10% solution