# physics

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1 kg of ice at 0° C is mixed with 9 kg of water at 50° C (The latent heat of ice is 3.34x105 J/kg and the specific heat capacity of water is 4160 J/kg). What is the resulting temperature?

• physics -

Heat into ice = 1*3.34*10^5 +(T-0)(4160)
Heat out of water = 4160 (50-T)(9)

set equal and solve for T

• physics -

omg thank you so much!!

• physics -

but ? where did the 1.3 come frm

• physics -

1*3 is one times 3
1 kilogram times latent heat of ice

• physics -

budhu hai kya tu

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