Physics
posted by Anonymous .
A baseball is hit off a 1 meter high tee at an angle of 25 degrees and at a speed of 43 m/s. How far to the nearest tenth of a meter does it travel horizontally?

vertical problem
Vi = 43 sin 25 = 18.17
v = Vi  9.8 t
0 = 18.17  9.8 t at top
t to top = 1.85 seconds to top
h = 1 + 18.17 (1.85)  4.9 (1.85)^2
h = 1 + 33.61  16.77 = 17.8 m at top at 1.85 s
now fall from 17.8 m
17.8 = 4.9 t^2
t = 1.91 s to fall
total time in air = 1.85+1.91 = 3.76 s in the air
how far, horizontal problem
u = constant horizontal speed = 43 cos 25 = 39 m/s
distance = 39 * 3.76 = 147 meters
a football field and more than a half