College Algebra

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Please help me

Divide.
(9x^3-10+19+6x^4)/(-2x^2+3x-3)

Write your answer in the form Q(x)+ R(x)/ -2x^2+3x-3,
where Q(x) is the quotient and R(x) is the remainder.

  • College Algebra -

    First rearrange and simplify the numerator to:
    6x^4 + 9x^3 + 9

    Just divide as your would with any long division problem.

    If you post your answer I can tell you if you are correct.

    Is there something in particular you do not understand?

  • College Algebra -

    Just not good at division

  • College Algebra -

    I'll try, but the formatting here doesn't allow for easy alignment of columns.

    xxxxxxxxxxxxx-3x^2 - 9x - 9
    -2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9
    ------------6x^4 - 9x^3 + 9x^2
    subtraction-------18x^3 - 9x^2
    ------------------18x^3 - 27x^2 + 27x
    subtraction-------------18x^2 - 27x + 9
    ------------------------18x^2-27x + 27
    subtractionxxxxxxxxxxxxxxxxxxxxxxx -18

    Answer in the form
    Q(x)+ R(x)/ -2x^2+3x-3,
    -3x^2 - 9x - 9 + -18/(-2x^2 + 3x - 3)

    I don't know how you will follow this because of the formatting.

  • College Algebra -

    Ok I will try to figure it out and ask if I need anymore questions. thanks for your help

  • College Algebra -

    You're welcome and good luck :).

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