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Show that 1cos2A/Cos^2*A = tan^2*A 1cos2A/Cos^2*A = [Cos^2(A)  Cos(2A)]/Cos^2(A). Substitute: Cos(2A) = 2Cos^2(A)  1: [1  Cos^2(A)]/Cos^2(A)= Sin^2(A)/Cos^2(A) = tan^2(A) 
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it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost … 
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