# MATH ALGEBRA

posted by .

How would u figure this question out?

Does this system of linear equation have a solution of (-3,4)?

2x-3 = 6
y = 3x-13

Do u just substitute the numbers or something?

• MATH ALGEBRA -

Yes, just substitute in both equations

1st:
Left Side = 2x-3 = 2(-3) - 3 = -9
but RS = 6, so the values don't even work in the first equation, you can stop here
(-3,4) is NOT a solution

I have a feeling that your first equation should have been
2x - 3y = 6
in that case:
LS - 2(-3) - 3(4) = -6
RS = +6
No point even trying the second

So no good either.

• MATH ALGEBRA -

Yes, sorry Reiny I had forgotton the Y. And thanks for the explanation:)

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