MATH ALGEBRA
posted by Anonymous .
How would u figure this question out?
Does this system of linear equation have a solution of (3,4)?
2x3 = 6
y = 3x13
Do u just substitute the numbers or something?

Yes, just substitute in both equations
1st:
Left Side = 2x3 = 2(3)  3 = 9
but RS = 6, so the values don't even work in the first equation, you can stop here
(3,4) is NOT a solution
I have a feeling that your first equation should have been
2x  3y = 6
in that case:
LS  2(3)  3(4) = 6
RS = +6
No point even trying the second
So no good either. 
Yes, sorry Reiny I had forgotton the Y. And thanks for the explanation:)
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