algebra

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9x+6y=3 and 3x-7y=-26 using the substitution method

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    9x+6y=3 (1)

    3x-7y=-26 (2)

    using substitution method in (1) we get
    9x+6y=3

    dividing by 3 both side we get

    3x+2y=1

    taking 2y to the other side (here 2y in + so when we change its side it will be -)
    3x=1-2y

    (here 3 is multiply with x so when it goes other side sign will change in divide)

    x=(1-2y)/3 (3)

    3x-7y=-26 (2)

    putting the value of x in (2) from (3)

    3*(1-2y)/3-7y=-26

    (3 will cancel by 3)

    1-2y-7y=-26

    1-9y=-26

    taking constant no. Same side

    -9y=-26-1

    -9y=-27

    (both sides minus sign will cancel by each other)
    9y=27

    y=27/9
    y=3

    putting the value of y in (3)
    x=(1-3*2)/3

    x=(1-6)/3

    x=-5/3

    (u can check ur ans by putting the value of 'x' and 'y' in (1) and (2))

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