express(2/3x-1)^2 as a trinomial?
recall that
(a+b)^2 yields the trinomial
a^2 + 2ab + b^2
apply it to your question.
To express (2/3x - 1)^2 as a trinomial, we need to expand the square and simplify the expression.
First, let's rewrite the expression as (2/3x - 1) * (2/3x - 1).
To expand this, we'll use the FOIL method, which stands for First, Outer, Inner, Last.
The First terms are (2/3x) * (2/3x) = 4/9x^2.
The Outer terms are (2/3x) * (-1) = -2/3x.
The Inner terms are (-1) * (2/3x) = -2/3x.
The Last terms are (-1) * (-1) = 1.
Now, we can combine all the terms to form a trinomial:
4/9x^2 - 2/3x - 2/3x + 1.
Simplifying further, we can combine like terms:
4/9x^2 - 4/3x + 1.
So the trinomial expression for (2/3x - 1)^2 is 4/9x^2 - 4/3x + 1.