Geometry
posted by Ivan .
If a rectangular lot measures 120 ft. x 80 ft., and 10 foot set backs are required from each lot line, how much area is left? If a kennel for 50 dogs requires 12,500 square feet, how many dogs can be accommodated in the small rectangle?

1)
L = 120  20 = 100
w = 80  20 = 60
A = Lw
A = 100 * 60
A = 6000 sq ft
2)
12,500/50 = 250 sq ft/dog
6000/250 = 24 dogs