math helper plese
posted by Kelly .
2 isosceles triangles have the same height. The slopes of the sides of triangle A are double the
slopes of the corresponding sides of triangle B. How do the lengths of their bases compare?
A. The base of A is quadruple that of B. The base of A is double that of B.
C. The base of A is half that of B.
D. The base of A is one quarter that of B.
I thought it would be B, but its A, how?
let the height of both triangles be h
let the base of triangle A be 2x
let the base of triangle B be 2y
slope of side of A = h/x
slope of side of B = h/x
but h/x = 2 (h/y
1/x = 2/y
y = 2x
x = (1/2)y ----> base of A is half that of B
I still dont' get how it the base is half the size?