trig
posted by deena .
sorry  here it is
simplify this expression : (x^3 y)/(y^(1/2) x^(2) ) when x is not = 0, and y is not equal to 0
thank you

trig 
Anonymous
WE know that [formula a^m/a^n=a^(mn)]
where m>n it means in division when base (means 'a') are same with different power('m' and 'n') then powers are subtracted
x^3*y/[(y^1/2)*(x^2)]
=x^3(2)*y^(11/2)
=x^3+2*y^1/2
=x^5*y^1/2
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