use the quadratic formula to solve for x, 3x^2 + x -8=0

x = - b ± (sqrt(b^2 - 4ac))/2a

3x^2 + x - 8 = 0

a = 3, b = 1, c = -8

what do you need help with?
I gave you the formula, you give it a try, post your work if you get stuck.

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In google type

"quadratic equation online"
when you see list of results click on:

webgraphingcom/quadraticequation_quadraticformula.jsp

Whenn this page be open in rectacangle type your equation,and click option solve it

and you will see solution Step-by-step

I really need help with my math/209 I took 208 3 years ago, and now I am taking the second part and I am so lost. How can I get some help.

To solve the quadratic equation 3x^2 + x - 8 = 0 using the quadratic formula, follow these steps:

Step 1: Identify the coefficients of the quadratic equation. In this case, a = 3, b = 1, and c = -8.

Step 2: Plug the values of a, b, and c into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)

Step 3: Substitute the values into the quadratic formula:
x = (-(1) ± √((1)^2 - 4(3)(-8))) / (2(3))

Step 4: Simplify the expression inside the square root:
x = (-1 ± √(1 + 96)) / 6
= (-1 ± √97) / 6

Therefore, the solutions for x are:
x = (-1 + √97) / 6
x = (-1 - √97) / 6

These are the two possible solutions to the equation 3x^2 + x - 8 = 0 using the quadratic formula.