physics
posted by Daniel .
A mass of 10kg is placed on the top of a plane inclined at 45 degrees to the horizontal and allowed to slide down. What is the acceleration of the mass if the frictional force opposing is 3.2N.

mg = 10kg * 9.8 = 98N @ 45deg.
Fp = 98*sin(45) = 69.3N = Force acting parallel to plane and downward.
Fn = Fp  Ff = 69.3  3.2 = 66.1N.
a = Fn / m = 66.1 / 10kg = 6.61m/s^2.
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