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math

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13y=10
x+y+z=39
16x=13z

  • math -

    from the 1st : y = 10/13
    from the 3rd: x = 13z/16

    sub into 2nd
    x+y+z = 39
    (13z/16) + 10/13 + z = 9
    times 208
    169z + 160 + 208z = 1872
    377z = 1712
    z = 1712/377

    now back-substitute ....

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