physics
posted by j .
Okay, I have an example problem that I'm trying to solve that comes with the answer; I'm just trying to figure out what to do.
A man jogs at a speed of 1.8 m/s. His dog
waits 2 s and then takes off running at a speed
of 4 m/s to catch the man.
How far will they have each traveled when
the dog catches up with the man?
Correct answer: 6.54545 m.
I think that I'll need to set the two equations equal and that I see that I'm given time and two sets of constant velocity but I looked at all my equations that I have and I can't figure out what equation I need.
Any help would be welcome.

V=d/t
d=V*t
Let t be the time the man is jogging. t2 is the time the dog is running (since the dog waits 2s). When they catch up with each other displacement will be equal.
(4m/s)(t2)=(1.8m/s)(t)
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