Physics

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Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision?
Support you answer with a calculation.

Please help me solve this ASAP, thank you.

  • Physics -

    Sorry Train A is sidetracked onto Train B's train track, which is 100 m ahead of Train A**

  • Physics -

    v=0
    u=36m/s
    a=3m/s^2
    t=?
    v=u+at
    0=36m/s-3m/s^2t
    0=-36=3t
    t=36/2
    =18 seconds.

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