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The position of a ball as its kicked upwards is measured as
y(t) =−(4.9 t^2 + 20t + 0.50)m,
where t is measured in seconds. Find the vertical component of velocity and acceleration of the ball as a function of time. If the ground is located at yg = 0, find the time at which the ball hits the

  • physics/dynamics -

    Your equation is wrong with a minus sign parentheses outside the paretheses. Please verify that you copied it right.

    It should be
    y(t) = −4.9 t^2 + 20t + 0.50 (meters)

    Zero vertical velocity is attained when
    dy/dt = -9.8 t + 20 = 0
    t = 20/9.8 = 2.04 seconds

    It hits the ground when
    −4.9 t^2 + 20t + 0.50 = 0

    I suggest you use the quadratic equation and take the positive root.

    You should get 4.016 s

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