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a metal wire 1.0 mm in diameter and 2.0 m long hangs vertically with a 5.0 kg mass suspended from it. if the wire stretches 1.2 mm under the tension, what is the value of the young's modulus for metal?

  • physics -

    Stress = E*strain
    E is Young's modulus

    E*(delta L/L) = M*g/(pi*R^2)

    deltaL/L - 1.2/2000 = 6*10^-4
    is the strain

    M*g/(pi*R^2) = 6.2*10^7 N/m^2

    Solve for E. It is about 10^11 N/m^2

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