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Assume the probability is 1/2 that a child born is a girl. If a family has three children, what is the probability that they have a) exactly one girl b) at most two boys?

  • Math -

    a) So it could be
    GBB or BGB or BBG
    prob of that is 3(1/2)(1/2)(1/2) = 3/8

    b) at most 2 boys ---> cannot have BBB
    which has a prob of 1/8

    so your case has prob of 1 - 1/8 = 7/8

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