algebra
posted by Anonymous .
Two rectangles have the same width. The length of one is 1 foot longer than the width. The length of the other is 2 feet longer than the width. The larger rectangle has 5 more square feet than the smaller. What is the width of the rectangles

Area=lw
w=width
w=width of 1st, w=width of 2nd (since their widths are equal)
l=length
l=w+1 length of 1st
l=w+2 length of 2nd
Area of 1st = w(w + 1)
Area of 2nd = w(w + 2)  5
Therefore,
w(w + 1) = w(w + 2)  5
Solve for w 
if the length is 7 meters longer than its width. what is the width of the object if the perimeter is equal to 98
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