Statistics and Probability
posted by Giselle .
it has been estimated that about 30% of frozen chickens contain enough salmonella bacteria to cause illness if imprperly cooked. A consumer purchases 12 frozen chickens. What is the probability that the consumer will have more than 6 contaminated chickens?
A) .882
B) .961
C) .039
D) .079

prob of causing illness = .3
prob of not causing illness = .7
so you want
prob(7of 12will cause illness) + prob(8of 12will cause illness)+ ... + prob(12of 12will cause illness)
= C(12,7)(.3)^7(.7)^5 + C(12,8)(.3^8)(.7^4) + ... +C(12,12)(.3^12)
you do the button pushing. 
Thank you Soo much!

welcome