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whats the vertex of 4y^2+4y-16x+13=0?

  • math -

    rearrange, then complete the square ....
    16x = 4y^2 + 4y + 13
    4x = y^2 + y + 1/4 - 1/4 + 13/4
    4x = (y + 1/2)^2 -1/4 + 13/4
    4x = (y+1/2)^2 - 3
    x = (1/4)(y + 1/2)^2 - 3/4

    can you read the vertex from that?

  • math -

    so is it (-3/4,-1/2)?

  • math -

    yes, good for you to notice that you had to read the x and y in inverse form.

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