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if a simple pendulum with length 1.50 m makes 72 oscillations in 3 minutes. what is the acceleration of the gravity at its location ?

  • science -

    let I = m L^2
    theta = A sin wt
    torque = -m g L sin theta = approx -m g L theta
    dTheta/dt = A w cos w t
    d^2Theta/dt^2 = -Aw^2 sin wt = - w^2 Theta
    I d^2Theta/dt ^2 = m g L theta
    m L^2 w^2 = m g L
    w^2 = g/L
    (YOU MIGHT START HERE IF FORMULA IN YOUR BOOK)
    2 pi f = sqrt(g/L)
    f = 72/180
    2 pi (72/180) = sqrt (g/1.5)
    6.317 = g/1.5
    g = 9.47 m/s^2

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