According to the following reaction, how many moles of Fe(OH)2 CAN FORM FROM 175.0 mL of 0.227 M LiOH soultion? Assume that there is an excess of FeCl2
FeCl2(aq)+ 2 LiOH(aq)-(Oh)2(s)+2LiCl(aq)
I have no clue how to approach this problem? Could anyone help me? I do not know were to begin. The answer is not important i just need to know how to solve. Thank you
Here is a worked example of a stoichiometry problem. Just follow the steps. This is a good example for you to keep.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of moles of Fe(OH)2 that can form from a given volume and concentration of LiOH solution, you need to follow a few steps:
Step 1: Write and balance the chemical equation:
FeCl2(aq) + 2 LiOH(aq) → Fe(OH)2(s) + 2 LiCl(aq)
Step 2: Determine the moles of LiOH:
To do this, you need to use the equation: concentration (M) = moles (mol) / volume (L).
Here, you have the concentration of LiOH as 0.227 M, and the volume as 175.0 mL (which needs to be converted to liters).
0.227 M = moles (mol) / 0.175 L
Rearranging the equation, you can calculate the moles of LiOH: moles (mol) = 0.227 M * 0.175 L
Step 3: Determine the moles of Fe(OH)2:
From the balanced equation, you can see that 1 mole of FeCl2 reacts with 2 moles of LiOH to produce 1 mole of Fe(OH)2. This means that the moles of Fe(OH)2 will be equal to half the moles of LiOH calculated in step 2.
moles of Fe(OH)2 = moles of LiOH / 2
Step 4: Calculate the moles of Fe(OH)2:
Substitute the value obtained from step 2 into step 3 to calculate the moles of Fe(OH)2.
Remember to always double-check your units and conversions while solving the problem.
To determine the number of moles of Fe(OH)2 that can form from the given LiOH solution, we can use the concept of stoichiometry and the given concentration of LiOH.
Step 1: Write down the balanced chemical equation for the reaction:
FeCl2(aq) + 2 LiOH(aq) -> Fe(OH)2(s) + 2 LiCl(aq)
Step 2: Calculate the number of moles of LiOH in the given solution.
To find the number of moles, we multiply the volume (in liters) by the concentration (in moles per liter):
mole LiOH = volume LiOH (in liters) x concentration of LiOH (in moles per liter)
Given:
volume LiOH = 175.0 mL = 0.175 L (convert mL to L)
concentration of LiOH = 0.227 M
Moles of LiOH = 0.175 L x 0.227 moles/L
Step 3: Use the stoichiometry of the balanced equation to determine the moles of Fe(OH)2 that can form.
From the balanced equation, we see that for every 2 moles of LiOH, 1 mole of Fe(OH)2 is formed.
Moles of Fe(OH)2 = Moles of LiOH / 2
Step 4: Calculate the moles of Fe(OH)2 using the values from Step 2 and Step 3.
Moles of Fe(OH)2 = (0.175 L x 0.227 moles/L) / 2
Solve this equation to find the moles of Fe(OH)2.