chem

posted by .

a 6.54 g sample consisting of a mixture of silver nitrate and sodium nitrate is dissolved in water. this mixture then reacts with barium chloride to for 3.50 g of silver chloride. calculate the percent by mass of silver nitrate in the first mixture

  • chem -

    2AgNO3 + BaCl2 ==> 2AgCl + Ba(NO3)2

    How many moles AgCl were formed? That is g/molar mass = moles = 3.50/143.32 = 0.0244 moles.

    Since 1 mole AgCl = 1 mole AgNO3, we must have had 0.0244 moles AgNO3 in the original sample and we convert to grams by g = moles x molar mass.

    Then percent AgNO3 = (mass AgNO3/mass sample)*100 = ??

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. science

    Consider a 1.50-g mixture of magnesium nitrate and magnesium chloride.After dissolving this mixture in water,0.500M silver nitrate is added dropwise until precipitate formation is complete. THe mass of the white precipitate formed …
  2. chemistry

    An aqueous solution of silver nitrate contains 5.00 g of silver nitrate. To this solution is added sufficient barium chloride to precipitate all the silver as silver chloride. What mass, in grams, of dry silver chloride can be obtained?
  3. chemistry

    The traditional method of analyzing the amount of chloride ion present in a sample was to dissolve the sample in water and then slowly add a solution of silver nitrate. Silver chloride is very insoluble in water, and by adding a slight …
  4. chemistry

    a mixture containing only sodium chloride and potassium chloride has a mass of 4 g. when this sample is dissolved in water and excess silver nitrate is added a white solid forms. after filreation and drying the solid silver chloride …
  5. Chemistry

    A mixture contains only CuCl2 and FeCl3. A 0.7391 g sample of the mixture is completely dissolved in water and treated with silver nitrate. if 86.91 mL of 0.1463 M silver nitrate soultion is needed to precipitate all the chloride as …
  6. Chemistry - Science

    A 6.70 g sample of a binary mixture of silver (I) nitrate and sodium nitrate is completely dissolved in water to make a solution. Aqueous barium chloride is then added to this solution in excess to form 3.60 g of silver chloride solid. …
  7. chemistry

    A mixture of 3.00 g of silver and copper metals was dissolved in excess nitric acid. Resulting salts, silver(I) nitrate and copper(II) nitrate, were isolated and dissolved in enough water to make 0.100 L of a solution with a total …
  8. chemistry

    A 15.0 g sample consisting of a mixture of silver nitrate and sodium nitrate is dissolved in water. This aqueous mixture then reacts with aqueous potassium chloride to form 3.97 g of solid. Calculate the percent by mass of silver nitrate …
  9. chemistry

    When silver nitrate reacts with barium chloride, silver chloride and barium nitrate are formed. How many grams of silver chloride are formed when 8.0 g of silver nitrate reacts with 15.0 g of barium chloride?
  10. Chemistry

    A 0.8870-g mixture of sodium chloride and potassium chloride is dissolved in water and silver nitrate is added. The AgCl that precipitates has a mass of 1.913 g. Calculate the percent by mass of potassium in the initial mixture。

More Similar Questions