i have to write this out in word form because it doesn't look rite when i use numbers...
What is the value of X when Y=7?
Problem: negative threeX to the 2nd power plus fourY minus one equals zero
2
-3x + 4y - 1 = 0
Please don't repost a question before checking for any replies on your previous post.
http://www.jiskha.com/display.cgi?id=1292296924
Secondly, don't switch names, first it was
Karrie, now it is Carrie.
To find the value of X when Y = 7, you need to substitute the value of Y into the equation and solve for X. Let's break it down step-by-step:
1. Start with the given equation: -3X^2 + 4Y - 1 = 0
2. Replace the variable Y with its value, which is 7: -3X^2 + 4(7) - 1 = 0
3. Simplify the equation: -3X^2 + 28 - 1 = 0
4. Combine like terms: -3X^2 + 27 = 0
5. Move the constant term to the other side of the equation: -3X^2 = -27
6. Divide both sides of the equation by -3 to isolate X^2: X^2 = 9
7. Take the square root of both sides to solve for X: X = ±√9
8. Simplify the square root of 9: X = ±3
So, when Y = 7, the value of X can be either 3 or -3.