# precalculus

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2. Simplify (8x^6 times 32y^5)^(1/2)

3. Approximate the real zeros of f(x)= 2x^4 + 3x^2 - 20.

• precalculus -

Let u = x^2 and solve
2u^2 -3u -20 = 0

That can be factored, to give
(2u +5)(u-4) = 0
u = 4 OR -5/2
x = sqrt4 or sqrt(-3/2)

The only REAL zeros are +2 and -2

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