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A fixed 0.15 kg solid-disk pulley with a radius of 0.075 m is acted on by a net torque of 6.8 m·N. What is the angular acceleration of the pulley?

  • Physics -

    angular acceleration =
    (Torque)/(Moment of inertia)

    For a solid disc,
    Moment of Inertia = (1/2) M R^2

    The answer will be in radians/second^2

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