25.00 mL of a 2.00 M solution of NaCl is diluted to a final volume of 100.0 mL. What is the concentration of NaCl in the final solution?
To find the concentration of NaCl in the final solution, we need to use the equation for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (2.00 M)
V1 = initial volume of the solution (25.00 mL)
C2 = final concentration of the solution (unknown)
V2 = final volume of the solution (100.0 mL)
Let's plug in the values and solve for C2:
(2.00 M)(25.00 mL) = C2(100.0 mL)
(2.00 M)(25.00 mL) / 100.0 mL = C2
50.0 mol/L / 100.0 mL = C2
0.500 M = C2
Therefore, the concentration of NaCl in the final solution is 0.500 M.