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Show that 2i and 1-i are both solutions to the equation x^2-(1+i)x+(2+2i)=0 but their conjugates,-2i and 1+i are not. Then explain why this does not violate the Conjugate Zeros Theorem.

  • Mathematics -

    The conjugate zeroes theorem says:
    "If f(x) is a polynomial having only real coefficients and if a + bi is a zero of f(x), then a – bi is also a zero of f(x)."

    Does the given equation satisfy all the conditions required for the theorem to apply?

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