Calculus

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∫4 [( ( ln(z) )^ 2)/z] dz

∫[( 7 e^(7 √x))/ √x] dx

∫[(2 x + 5)/( x^2 + 5 x + 2)] dx

  • Calculus -

    Let x^2 +5x +2 = u
    That makes du = (2x +5) dx
    So your integral becomes du/u = ln u = ln (x^2 + 5x + 2)

    Try a similar substitution technique with the others.

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