# Calculus

posted by
**Hannah**
.

Find the unique solution to the differential equation

y"?1y'?6y=?24(t^2)+10t+41

satisfying the initial conditions y(0)=?6 and y'(0)=?26

posted by
**Hannah**
.

Find the unique solution to the differential equation

y"?1y'?6y=?24(t^2)+10t+41

satisfying the initial conditions y(0)=?6 and y'(0)=?26