A giant excavator (used in road construction) can apply a maximum vertical force of 2.25×105 N. If it can vertically accelerate a load of dirt at 0.200 m/s2, what is the mass of that load? Ignore the mass of the excavator itself.
To find the mass of the load, we can use Newton's second law of motion:
F = m * a
Where:
F = force applied (2.25×10^5 N)
m = mass of the load (unknown)
a = acceleration (0.200 m/s²)
Rearranging the equation, we have:
m = F / a
Substituting the given values, we get:
m = 2.25×10^5 N / 0.200 m/s²
m ≈ 1.125×10^6 kg
Therefore, the mass of the load is approximately 1.125×10^6 kg.
To find the mass of the load, we can use Newton's second law of motion, which states that the force applied to an object equals the mass of the object multiplied by its acceleration:
Force = mass × acceleration
In this case, the force applied by the excavator is given as 2.25×10^5 N, and the vertical acceleration of the load is 0.200 m/s^2.
Rearranging the equation, we can solve for the mass:
mass = Force / acceleration
Substituting the given values:
mass = 2.25×10^5 N / 0.200 m/s^2
Calculating the result:
mass = 1.125×10^6 kg
Therefore, the mass of the load of dirt is approximately 1.125×10^6 kg.